PROGRAM TO SIMULATE MVT AND MFT MEMORY MANAGEMENT TECHNIQUES
#include<stdio.h>
#include<conio.h>
main()
{
int ms, bs, nob, ef,n, mp[10],tif=0;
int i,p=0;
clrscr();
printf("Enter the total memory available (in Bytes) -- ");
scanf("%d",&ms);
printf("Enter the block size (in Bytes) -- ");
scanf("%d", &bs);
nob=ms/bs;
ef=ms - nob*bs;
printf("\nEnter the number of processes -- ");
scanf("%d",&n);
for(i=0;i<n;i++)
{
printf("Enter memory required for process %d (in Bytes)-- ",i+1);
scanf("%d",&mp[i]);
}
printf("\nNo. of Blocks available in memory -- %d",nob);
printf("\n\nPROCESS\tMEMORY REQUIRED\t ALLOCATED\tINTERNAL FRAGMENTATION");
for(i=0;i<n && p<nob;i++)
{
printf("\n %d\t\t%d",i+1,mp[i]);
if(mp[i] > bs)
printf("\t\tNO\t\t---");
else
{
printf("\t\tYES\t%d",bs-mp[i]);
tif = tif + bs-mp[i];
p++;
}
}
if(i<n)
printf("\nMemory is Full, Remaining Processes cannot be accomodated");
printf("\n\nTotal Internal Fragmentation is %d",tif);
printf("\nTotal External Fragmentation is %d",ef);
getch();
}
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INPUT
Enter the total memory available (in Bytes) -- 1000
Enter the block size (in Bytes)-- 300
Enter the number of processes – 5
Enter memory required for process 1 (in Bytes) -- 275
Enter memory required for process 2 (in Bytes) -- 400
Enter memory required for process 3 (in Bytes) -- 290
Enter memory required for process 4 (in Bytes) -- 293
Enter memory required for process 5 (in Bytes) -- 100
No. of Blocks available in memory -- 3
OUTPUT
PROCESS MEMORY-REQUIRED ALLOCATED INTERNAL-FRAGMENTATION
1 275 YES 25
2 400 NO -----
3 290 YES 10
4 293 YES 7
Memory is Full, Remaining Processes cannot be accommodated
Total Internal Fragmentation is 42
Total External Fragmentation is 100
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MVT MEMORY MANAGEMENT TECHNIQUE
#include<stdio.h>
#include<conio.h>
main()
{
int ms,mp[10],i, temp,n=0;
char ch = 'y';
clrscr();
printf("\nEnter the total memory available (in Bytes)-- ");
scanf("%d",&ms);
temp=ms;
for(i=0;ch=='y';i++,n++)
{
printf("\nEnter memory required for process %d (in Bytes) -- ",i+1);
scanf("%d",&mp[i]);
if(mp[i]<=temp)
{
printf("\nMemory is allocated for Process %d ",i+1);
temp = temp - mp[i];
}
else
{
printf("\nMemory is Full");
break;
}
printf("\nDo you want to continue(y/n) -- ");
scanf(" %c", &ch);
}
printf("\n\nTotal Memory Available -- %d", ms);
printf("\n\n\tPROCESS\t\t MEMORY ALLOCATED ");
for(i=0;i<n;i++)
printf("\n \t%d\t\t%d",i+1,mp[i]);
printf("\n\nTotal Memory Allocated is %d",ms-temp);
printf("\nTotal External Fragmentation is %d",temp);
getch();
}
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INPUT
Enter the total memory available (in Bytes) -- 1000
Enter memory required for process 1 (in Bytes) -- 400
Memory is allocated for Process 1
Do you want to continue(y/n) -- y
Enter memory required for process 2 (in Bytes) -- 275
Memory is allocated for Process 2
Do you want to continue(y/n) -- y
Enter memory required for process 3 (in Bytes) -- 550
OUTPUT
Memory is Full
Total Memory Available -- 1000
PROCESS MEMORY-ALLOCATED
1 400
2 275
Total Memory Allocated is 675
Total External Fragmentation is 325
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